# Reciprocal Rank Fusion on two short rankings

vector ranking : [A, B, C, D]
keyword ranking: [C, A, E, B]

--- k = 1 ---
A  score 0.83333   (vector rank 1, keyword rank 2)
C  score 0.75000   (vector rank 3, keyword rank 1)
B  score 0.53333   (vector rank 2, keyword rank 4)
E  score 0.25000   (vector rank 0, keyword rank 3)
D  score 0.20000   (vector rank 4, keyword rank 0)

--- k = 60 ---
A  score 0.03252   (vector rank 1, keyword rank 2)
C  score 0.03227   (vector rank 3, keyword rank 1)
B  score 0.03175   (vector rank 2, keyword rank 4)
E  score 0.01587   (vector rank 0, keyword rank 3)
D  score 0.01563   (vector rank 4, keyword rank 0)

--- k = 1000 ---
A  score 0.00200   (vector rank 1, keyword rank 2)
C  score 0.00200   (vector rank 3, keyword rank 1)
B  score 0.00199   (vector rank 2, keyword rank 4)
E  score 0.00100   (vector rank 0, keyword rank 3)
D  score 0.00100   (vector rank 4, keyword rank 0)

--- the arithmetic for A at k = 60 ---
rank 1 in the vector list: 1/(60+1) = 0.01639
rank 2 in the keyword list: 1/(60+2) = 0.01613
sum = 0.03252

--- an item in one list only ---
E is rank 3 in the keyword list and absent from the vector list: 1/(60+3) = 0.01587
D is rank 4 in the vector list and absent from the keyword list: 1/(60+4) = 0.01563
