Claude
2ccf1d8d19
Co-Authored-By: Claude Sonnet 5.5 <[email protected]> Claude-Session: https://claude.ai/code/session_0146opDKBYtADXvkc39zdiyw
35 lines
1.2 KiB
Plaintext
35 lines
1.2 KiB
Plaintext
# Reciprocal Rank Fusion on two short rankings
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vector ranking : [A, B, C, D]
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keyword ranking: [C, A, E, B]
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--- k = 1 ---
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A score 0.83333 (vector rank 1, keyword rank 2)
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C score 0.75000 (vector rank 3, keyword rank 1)
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B score 0.53333 (vector rank 2, keyword rank 4)
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E score 0.25000 (vector rank 0, keyword rank 3)
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D score 0.20000 (vector rank 4, keyword rank 0)
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--- k = 60 ---
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A score 0.03252 (vector rank 1, keyword rank 2)
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C score 0.03227 (vector rank 3, keyword rank 1)
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B score 0.03175 (vector rank 2, keyword rank 4)
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E score 0.01587 (vector rank 0, keyword rank 3)
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D score 0.01563 (vector rank 4, keyword rank 0)
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--- k = 1000 ---
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A score 0.00200 (vector rank 1, keyword rank 2)
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C score 0.00200 (vector rank 3, keyword rank 1)
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B score 0.00199 (vector rank 2, keyword rank 4)
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E score 0.00100 (vector rank 0, keyword rank 3)
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D score 0.00100 (vector rank 4, keyword rank 0)
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--- the arithmetic for A at k = 60 ---
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rank 1 in the vector list: 1/(60+1) = 0.01639
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rank 2 in the keyword list: 1/(60+2) = 0.01613
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sum = 0.03252
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--- an item in one list only ---
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E is rank 3 in the keyword list and absent from the vector list: 1/(60+3) = 0.01587
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D is rank 4 in the vector list and absent from the keyword list: 1/(60+4) = 0.01563
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