Co-Authored-By: Claude Sonnet 5.5 <[email protected]> Claude-Session: https://claude.ai/code/session_017ic4b7rnC7jppGGdHGESvy
29 lines
1.5 KiB
Python
29 lines
1.5 KiB
Python
#!/usr/bin/env python3
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"""Third opinion: ask the `openssl kdf` command line tool (no Python crypto, no Java) for the RFC 5869 cases
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and for the first rows of cases.tsv, and compare with the expected OKM."""
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import subprocess, sys, re
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def openssl_hkdf(digest, ikm, salt, info, length):
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cmd = ["openssl", "kdf", "-keylen", str(length), "-kdfopt", f"digest:{digest}", "-kdfopt", f"hexkey:{ikm}",
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"-kdfopt", f"hexinfo:{info}", "-kdfopt", "mode:EXTRACT_AND_EXPAND"]
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if salt: cmd += ["-kdfopt", f"hexsalt:{salt}"]
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cmd += ["HKDF"]
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out = subprocess.run(cmd, capture_output=True, text=True, check=True).stdout.strip()
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return out.replace(":", "").lower()
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print(subprocess.run(["openssl", "version"], capture_output=True, text=True).stdout.strip())
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ok = bad = 0
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rfc = [("SHA256", "0b"*22, "000102030405060708090a0b0c", "f0f1f2f3f4f5f6f7f8f9", 42,
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"3cb25f25faacd57a90434f64d0362f2a2d2d0a90cf1a5a4c5db02d56ecc4c5bf34007208d5b887185865"),
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("SHA256", "0b"*22, "", "", 42,
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"8da4e775a563c18f715f802a063c5a31b8a11f5c5ee1879ec3454e5f3c738d2d9d201395faa4b61a96c8")]
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rows = [tuple(l.rstrip("\n").split("\t")) for l in open(sys.argv[1])]
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rows = [(h, i, s, n, int(L), o) for h, i, s, n, L, o in rows]
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for h, i, s, n, L, o in rfc + rows[::10]:
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got = openssl_hkdf(h, i, s, n, L)
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if got == o: ok += 1
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else:
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bad += 1; print("MISMATCH", h, i[:16], L)
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print(f"openssl kdf HKDF: {ok} of {ok+bad} cases match ({len(rfc)} RFC 5869 + every 10th row of cases.tsv)")
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sys.exit(1 if bad else 0)
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