In this blog post, we will explore an 8086 assembly language program designed to sort a list of numbers in ascending order. Sorting is a fundamental operation in computer science, and understanding how to implement it at the assembly level provides valuable insights into low-level programming and processor operations.​

The following assembly program sorts an array of numbers in ascending order using the bubble sort algorithm:

DATA SEGMENT
STRING1 DB 99H,12H,56H,45H,36H
DATA ENDS

CODE SEGMENT
ASSUME CS:CODE,DS:DATA
START: MOV AX,DATA
MOV DS,AX

MOV CH,04H

UP2: MOV CL,04H
LEA SI,STRING1

UP1: MOV AL,[SI]
MOV BL,[SI+1]
CMP AL,BL
JC DOWN
MOV DL,[SI+1]
XCHG [SI],DL
MOV [SI+1],DL

DOWN: INC SI
DEC CL
JNZ UP1
DEC CH
JNZ UP2

INT 3
CODE ENDS
END START

In this blog post, we’ll explore how to count the number of ‘0’s and ‘1’s in a binary string using an 8086 assembly language program. The following code snippet demonstrates this process:​

DATA SEGMENT
STR1 DB "00011100"
NZ DW ?
NO DW ?
DATA ENDS
CODE SEGMENT
ASSUME CS:CODE, DS:DATA
START:
MOV AX, DATA
MOV DS, AX
LEA SI, STR1
MOV BX, 00H
MOV DX, 00H
MOV CX, 08H
UP:
MOV AX, [SI]
ROR AX, 1
JNC ZE
INC BX
JMP DN
ZE:
INC DX
DN:
INC SI
DEC CX
JNZ UP
MOV NZ, DX
MOV NO, BX
INT 3
CODE ENDS
END START

This blog post presents an 8086 assembly program designed to count the number of 0s and 1s in a given 16-bit number. We’ll explore the bit manipulation techniques used and analyze the program’s execution flow.

In this blog post, we will explore an 8086 assembly language program designed to convert a binary number into its Binary-Coded Decimal (BCD) format. This conversion is essential in applications where binary numbers need to be represented in a decimal-like format, such as digital displays or interfaces that require human-readable numbers.

The following assembly program performs the conversion:

DATA SEGMENT
NO1 DB "1001000000110110"
D1 DW 4 DUP (?)
DATA ENDS
CODE SEGMENT
ASSUME CS:CODE, DS:DATA
START:
MOV AX, DATA
MOV DS, AX
LEA SI, NO1
LEA DI, D1
MOV CX, 04H
TOP:
MOV BX, 00H
MOV AX, [SI]
ROR AX, 1
JNC P2
ADD BX, 08H
P2:
INC SI
MOV AX, [SI]
ROR AX, 1
JNC P3
ADD BX, 04H
P3:
INC SI
MOV AX, [SI]
ROR AX, 1
JNC P4
ADD BX, 02H
P4:
INC SI
MOV AX, [SI]
ROR AX, 1
JNC P5
ADD BX, 01H
P5:
MOV [DI], BX
INC DI
INC SI
DEC CX
JNZ TOP
INT 3
CODE ENDS
END START

​In this blog post, we’ll explore how to convert a BCD (Binary-Coded Decimal) number into its binary equivalent using an 8086 assembly language program. The following code snippet demonstrates this process:

DATA SEGMENT
NO1 DB "9036"
D2 DB ?
D1 DB 16 DUP(?)
DATA ENDS
CODE SEGMENT
ASSUME CS:CODE, DS:DATA
START:
MOV AX, DATA
MOV DS, AX
LEA SI, NO1
LEA DI, D1
MOV CX, 04H
TOP:
MOV AL, [SI]
MOV DX, 0CH
UP1:
ROL AX,1
DEC DX
JNZ UP1
AND AX, 1111000000000000B
MOV DX, 04H
UP2:
ROL AX, 1
JNC DN
MOV BX, 1
MOV [DI], BX
JMP DN2
DN:
MOV BX, 0
MOV [DI], BX
DN2:
INC DI
DEC DX
JNZ UP2
INC SI
DEC CX
JNZ TOP
INT 3
CODE ENDS
END START