In this blog post, we’ll explore how to reverse an array using an 8086 assembly language program. We will walk through the logic, the step-by-step execution, and provide a working code snippet to illustrate the process.

Overall Process:

1. The program initializes registers and sets up pointers to the source (ARR) and destination (REV_ARR) arrays.
2. It processes each element of the original array, copying it in reverse order to the destination array.
3. After processing all elements, the program terminates, leaving the reversed array in memory.

8086 Assembly Code:

DATA SEGMENT
STR1 DB 01H,02H,05H,03H,04H
STR2 DB 5 DUP(?)
DATA ENDS

CODE SEGMENT
ASSUME CS:CODE, DS:DATA
START:
MOV AX, DATA
MOV DS, AX
LEA SI, STR1
LEA DI, STR2+4
MOV CX, 05H

BACK: CLD
MOV AL, [SI]
MOV [DI], AL
INC SI
DEC DI
DEC CX
JNZ BACK

INT 3
CODE ENDS
END START

A palindrome is a word, phrase, or sequence that reads the same forward and backward. This 8086 assembly program determines whether a given string is a palindrome by reversing the string and comparing it to the original.

The program follows these steps:

1. Initialize the Data Segment: Load the string to be checked.
2. Reverse the String: Store the reversed string in another memory location.
3. Compare the Original and Reversed Strings: Use CMPSB to compare byte-by-byte.
4. Print the Result: Display whether the string is a palindrome or not.

In this blog post, we’ll explore how to perform a block transfer using an 8086 assembly language program. The following code snippet demonstrates this process:

DATA SEGMENT
STRING1 DB 01H,02H,03H,04H,05H
STRING2 DB 4 DUP(0)
DATA ENDS

CODE SEGMENT
ASSUME CS:CODE,DS:DATA
START: MOV AX,DATA
MOV DS,AX
MOV ES,AX
LEA SI,STRING1
LEA DI,STRING2
MOV CX,05H
CLD
REP MOVSB
INT 3
CODE ENDS
END START